Reset Label via FlexScript

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a600 asked Apr 8, '25 Felix Möhlmann commented Apr 10, '25

Reset Label via FlexScript

We are trying to assign labels of integer value to processors via FlexScript. See code below.

We accidentally ran this code multiple times. Now, the type of the label is an array with multiple duplicate integers.

We want to revert back to the original integer value we assigned. We also want these labels to be static. How should we go about this?

See the original code:

clearconsole;

int numRows = Group("Sourcing Group").length;

Array myGroups = ["Sourcing Group", "Conditioning Group", "Finishing Group", "Packing Group", "Distribution Group"];

for (int i = 1; i <= myGroups.length; i++) {

for(int j = 1; j <= numRows; j++){

Object processor = Group(myGroups[i]);

processor.location = j;

print(j);

}

print(i);

}

Software Version:

FlexSim 25.1.0

flexscript duplicate

5 |100000

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Answer 1 · 2025-04-09T11:41:38Z

Felix Möhlmann answered Apr 9, '25 Felix Möhlmann commented Apr 10, '25

location is an object property. If you want to set a label with that name, you have to use "processor.labels["location"].value = ...". It is recommended to avoid using such names. Using a capital letter at the start of label names makes sure that they do not coincide with property names.

The processor variable in your code is assigned a reference to an entire group, instead of a single object. If I understood your goal correctly (number the objects in each group from 1 to N), then the code should look like the following,

Array myGroups = ["Sourcing Group", "Conditioning Group", "Finishing Group", "Packing Group", "Distribution Group"];
Group curGroup;
for(int i = 1; i <= myGroups.length; i++)
{
    curGroup = Group(myGroups[i]);
    for(int j = 1; j <= curGroup.length; j++)
    {
        Object processor = curGroup[j];
        processor.Location = j;
    }
}

· 4

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Alixe commented · Apr 09 at 02:08 PM

Thank you for your answer! Does this code create the label Location, or does it assume it already exist? Is there a way to delete the original label location for all the objects in the group at once? Instead of clicking on the properties and deleting 1 by 1?

0 ·

Felix Möhlmann Alixe commented · Apr 09 at 03:11 PM

The dot-syntax "object.labelName = ..." will create the label if it does not exist or overwrite the value if it does. The long form would be "processor.labels.assert("Location").value = ..."

To remove the other label you can add this into the innermost for-loop. With "object.labels["labelName"]" you access the label node rathen than the value. This allows you to delete the node (or change its name, among other things).

if(objectexists(processor.labels["location"]))
{
    processor.labels["location"].destroy();
}

1 ·

Alixe Felix Möhlmann commented · Apr 09 at 06:27 PM

Thank you, that worked!

An additional question: can we set maximum content for processors using a reference to a Global Table? I tried but it says the field on accepts numbers.

Could we use Flexscript for this?

0 ·

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